1. First, for comparison;

   Triplet numbers in a dimension chain giving circa A → N →Z-numbers:

*431 in A2+U2.

Reduction or addition of 2 (H?) in relation to the triplet series, from 1506 to 1504?
   It could perhaps be interpreted in several ways. A potential possibility for some ams (His or Trp ?) to bind another 2 H ?
   Generally, +/- 2H is a main theme in biochemistry; -2H in the citrate cycle for instance.

2.   Z-L-p-numbers generating A-numbers of R-chains:

Starting with a conclusion: Original mass numbers in atoms are expressed in the electron shells and steps between levels in these shells.

The hypothesis here was that electron shells of atoms in molecules, when these get activated or "excited", step by step are raised towards the surface, towards higher levels (corresponding to later steps in a dimension chain), with a simultaneous suppression of inner, deeper shells,
towards the Z-level, →the level of L-shell → the level of the p-orbital in atoms as C, N, O, S.

24 ams, R+B-chains:
Number of atoms C+O+N+S = 224. (H = 244)

With only 1 electron of the deeper levels suppressed in each step, from atoms C-N-O-S, we get the step by step reduction with 224 from the Z-number, giving following result:

*(In 1st base grouping, +/-1 in 2nd base grouping.)

The presumed excitation in Z-numbers generates - reflects - reveals (?) the mass numbers doubled in different stages.
The L-shells in the atoms seem to be responsible for the R-chains of ams.

Note:
- In the 6th step, at number 416, the value of charge of the C-atom is Zero.

- 416 is the difference between mass sums of the A+U-group and the G+C-group, R-chains, 960 - 544.

- Sum of "phases" 2 and 3 1536 + 1312 = 2848.
2848 = A-number for 24 ams R+B-chains in peptide binding

Interval 224 in each step = 4 x 56: 56 A = B-chain in peptide binding.

1760 - 416 = 1344 = 24 B-chains in peptide binding.

Sum of all stages from 1536 to 416 = 24 x 244, the sum of H-atoms.

Compare the numbers of the "triplets" in point 1 from the dimension chain:
   543 x 2 = 1086 +2   = 1088
   432 x 2 = 864 - 0     =   864
   321 x 2 = 642 - 2     =   640
   210 x 2 = 420 - 4     =   416

3. Series of "phases" for R- and B-chains taken separately:
    Electron reduction as activation towards the surface:

24 ams:
R-chains:   104 atoms C-N-O-S (+ 152 H-atoms). = - 104 per step
B-chains:   120 atoms C-N-O     (+ 92 H-atoms).  = - 120 per step

Z-sum B-chains = 932
Z-sum R-chains = 828. Difference 104 Z

B-chains give in first 4 phases the A-sum of 2 x 1504, the sum of R-chains.
2 x 1504 A

R-chains give in first 4 phases the A-sum of 2 x 24 B-chains in binding:
2 x 1344 A.

H-atoms, sum 92 in B-chains, become the rest in the 7th step in the B-chain series.
   The last two steps, 6th and 7th, give 2x 152, the sum of H-atoms in R-chains, in both B- and R-chains.

[And how if we count with only 20 amino acids? That means minus 1 x 187 per step:
   Z-sum of 20 ams = 1466:

*