What happens in electron shells?
- The disintegration series of Uranium to Pb 82 Z -
The orbital series as sums of the steps 5 - 4 - 3 - 2 - 1:
The point in this derivation of numbers is that we
easier can see the potential dividing of electrons within the orbitals:
According to one illustration in a scientific article
the d-orbital for example is divided into 1 circular formed electron
around the origin of the coordinate system, 3 electrons divided
along the 3 axes and 6 electrons (3 pairs), in the square quadrants
of the 3 planes.
A multiplication operator acting in the electron shells?
An angle change from ⊕
to ⊗, from addition to multiplication
relations in the e-shells, gives:
Through further division within orbitals the sum of
the electrons gets 10 units higher.
The disintegration series of 238U from 92 Z to Pb 82
Z goes through
8 alpha-steps = - 16 Z: compare the change above in f-orbital from
64 → 48.
6 beta-steps = + 6 Z: compare the change
above in d-orbital from 18 → 24.
Compare from Physics:
f-orbital, from step 4→3: Mass identified
as a property in this step. Mass reduction connected with alpha
d-orbital from step 3 → 2:
Charge identified as a property in this step. beta steps implying
change of charge.
Surely the distribution of electrons on different orbitals above
will not correspond to that which the physicists observe - if they
have time to observe what really happens?!.
The same type of operations for Uranium 235 and Thorium 232, 90
"Rearrangements" within the atoms:
235U: In this disintegration series we
have - 28 A:
beta-steps = - 14 Z, + 4 Z
β-steps in this series occur in first
steps in one(1) β+-radiation.
According to the suggestion above there should occur an inner β+-radiation.
(Possible to detection with its use as nuclear
232Th, 90 Z: In the disintegration series to Pb 207
A we have - 26 A, - 8 Z:
4 beta-steps = - 12 Z, + 4 Z.