What happens in electron shells?
 The disintegration series of Uranium to Pb 82 Z 
The orbital series as sums of the steps 5  4  3  2  1:
The point in this derivation of numbers is that we
easier can see the potential dividing of electrons within the orbitals:
According to one illustration in a scientific article
the dorbital for example is divided into 1 circular formed electron
around the origin of the coordinate system, 3 electrons divided
along the 3 axes and 6 electrons (3 pairs), in the square quadrants
of the 3 planes.
A multiplication operator acting in the electron shells?
An angle change from ⊕
to ⊗, from addition to multiplication
relations in the eshells, gives:
Through further division within orbitals the sum of
the electrons gets 10 units higher.
The disintegration series of ^{238}U from 92 Z to Pb 82
Z goes through
8 alphasteps =  16 Z: compare the change above in forbital from
64 → 48.
6 betasteps = + 6 Z: compare the change
above in dorbital from 18 → 24.
Compare from Physics:
forbital, from step 4→3: Mass identified
as a property in this step. Mass reduction connected with alpha
radiation.
dorbital from step 3 → 2:
Charge identified as a property in this step. beta steps implying
change of charge.
Surely the distribution of electrons on different orbitals above
will not correspond to that which the physicists observe  if they
have time to observe what really happens?!.
The same type of operations for Uranium 235 and Thorium 232, 90
Z?
Suggestions:
"Rearrangements" within the atoms:
^{235}U: In this disintegration series we
have  28 A:
 7
αsteps,
+ 4
betasteps =  14 Z, + 4 Z
βsteps in this series occur in first
steps in one(1) β+radiation.
According to the suggestion above there should occur an inner β+radiation.
(Possible to detection with its use as nuclear
fuel?)
^{232}Th, 90 Z: In the disintegration series to Pb 207
A we have  26 A,  8 Z:

6 alfasteps,
+
4 betasteps =  12 Z, + 4 Z.
*
