1. Velocity as ddegree steps:
Velocity is, according to hypothetical viewpoints in this
model, identified with the dimension degree step 1 →
0/00,
a polarization of a path into the physical quantities or
concepts Distance / Time.
Hence, Velocity, will be defined as a
translation of one ddegree into motion, the steps (or quantum
jumps) between ddegrees as changes of motion.
2. Velocity as a quotient between forces:
Velocity, as a quotient between Distance and Time as the
two poles of Motion, becomes a relation between a binding
force and a polarizing force, when these primarily are identified
with the 0pole and the 00pole respectively.
1/0
= 00 (polarizing force)
1 —/—> 0/00
1/00
= 0 (binding force)
3. Five quantum steps as a series of derivations ?
 With respect to what ? To Time or to
Distance ?
a) with respect to Time, v = velocity, a =
acceleration:
5 ——› 4 ——›
3 ——› 2 ——› 1 ——›
0/00
v ——› a —› m/s^{3}—›
m/s^{4}—› m/s^{5}
orccccccccccccf x acc—f^{2}
x a —f^{3} x a
Hence, if Mass in ddegree 3 (according to the proposals
on other pages) is coupled with negative (inward) acceleration,
then Charge, assumed as property in in ddegree 2, (as m/s^{3})
will not be connected with only negative velocity but with
frequency times negative acceleration.
If we take it the other way around :
5 —— 4 ——
3 —— 2 —— 1 —— 0/00
ccm/s^{5} ‹—
m/s^{4} ‹— m/s^{3 }‹—
a ‹—— v...........
or .f^{3} x a
— f^{2} x a — f x a.......................................
This seems more in accordance
with the high frequencies of matter as de Broglie waves.
But of course it does not agree with the comments on Einstein's
equation E = mc^{2} on the page about Time,
where we have velocity squared. For getting it to agree,
we have to interpret "Mass" as  f^{2}
/m =  1/(s^{2} x m).
b) Deriving with respect to Distance, m = meter ? :
5 ——› 4 ——›
3 ——› 2 ——› 1 ——›
0/00
......m^{4}/s —
m^{3}/s — m^{2}/s — m/s = v....
or in the other direction, which seems to
be a very silly result:
5 —— 4 —— 3 ———
2 ———1 —— 0/00
m/s 1/s
1/s x m^{1}
1/s x m^{2} 1/s x m^{3}
We leave the question about derivations here to the professional
physicists and mathematicians. In Einstein's general relativity theory
there is a formula about tensors (as secondary vectors)
which include a constant
k =  [8 πx
G)) / c^{4}
Reading this in a simpleminded way, we have
1). a negative sign which we can attribute
to negative values for c, the velocity of light,
2) 8 πwhich indicates 4 turns,
making a complicated kind of circular structure,
3) velocity c squared 2 times as denominator, inverted,
"underground".
Perhaps we should derive:
 1/c^{4} ‹—— 1/c^{3} ‹——
1/c^{2} ‹—— 1/c ,
to get some similarity with the views on Mass
and Charge in
the model here, Mass connected with negative (and inverted?)
acceleration and Charge connected with negative (and inverted
?) velocity.
4. Positive and negative velocity:
The relation between positive and negative velocity is
reasonably coupled with the complementary energy forms +/E.
and directions inwards / outwards.
If √ 1 for Time as oneway
directed gives the denominator of velocity, D/T, the velocity
gets complex. Equations with complex numbers give both real
and imaginary roots. The imaginary roots should be found
inwards the dimension chain, inwards in the matter.
A general assumption here is that when an a formula gives
imaginary roots, it should indicate that the analysis ought
to be moved to another level, underlying (or eventually
superposed?), or to another dimensional degree, in order
to get real values for the imaginary quantities or qualities.
(Number 10, the "Enumber" as sum of poles in
ddegree 4, with index as time squared, 1, gives the number
0,1. Multiplied with dimension chains as products and squared
in 2 steps gives:
0, 1 x 5x4x3x2x1→ x^{2}
→ x5x4x3x2x1 →
x^{2},
= [(10^{1} x 5!)^{2} x 5!]^{2}
=
= 2,985984 x 10^{8} = ca. light velocity in meter
/seconds (2,997925 x 10^{8}, year 1973).
