**I. The triplet series**, **x1**:

a) Reading triplet numbers in the elementary chain 5 - 0:

*(Most of this file from ***"17 short files"**, 05.)

The most elementary chain 5-4-3-2-1-0 read as triplets approximates
the sum of R-chains of ams read as two triplets: 2(543 + 210) =
1504 +2, or read as 4 triplets as in figure 15-1.

Expanded with triplets from 987 - 876 etc. the chain gives the approximate
whole mass of 24 ams. Intervals in each step = 111 sum up to 24
times B-chains à 74.

**Fig 15-1:** * Triplets
from elementary chain 5 to 0 and the same chain expanded:*

**A note about number 3282:**

Number 3282 is also the difference between products of base pair
numbers:

G 151, C 111, U 112, A 135:

2 x G x C = 33522

**|------- 3282**

2 z U x A = 30240

3282 = 6 x 547. 5 x 547 = 2735 = 20 ams, without the
double-coded ams.

(½ x 3282 = 1641 is said to have something
to do with a formula for first amount of prime numbers.)

A "condensed" or undeveloped elementary chain 5 - 0, dimensionally, written:

5 - 4 -3 - __2 - 1 - 0__, ~ 5433 ~ **546** ("before
disintegration") =**2 x 273**.

= 3

546 x 6 = **3276**, the sum of 24 ams R+B unbound.

b) A-N-Z-numbers of ams approximating the triplets:

**Fig 15-2:** * A-N-Z-
as triplets in codon groups:*

The chain A→> N→>Z
implies polarization steps from mass to charge as assumed in the background
model.

Cf. figure 13-8 **file 13**, approximate the same numbers halved.

[A connection with the ES-chain and its first nummber 5´ ?

**1/543 - 1/210** = - **292**,03. x 10-5 ]

__c) B-chains:__

In a peptide bond between ams their side-chains come to point in
opposite directions.

For the triplets 543 and 210 arranged in such a way, see figure
16-2 below,. When read in opposite directions, we get the B-chains
of 12 ams á 74 A = 888 as divided 543 + 345.

**Fig 15-3:** * Triplets
543, 210 written as neighbor R-chains in opposite directions:*

**888** = 12 B-chains `74. A division on numbers 543 and 345 gives:

543 **/** 12 = 45,25 ~ 45 A = COOH

345 **/** 12 = 28,75 ~ 29 A = H2N-CH

The B-chain gets approximately divided in the COOH-part 45 and H2N-CH-part
29.

Cf. the similar division in the ES-series
**here.**

345 —|— 210

135 = mass of
the A-base

135 is also mass of Meth, R+B, when losing its end group CH2 =
-14 at start of protein synthesis.

012 + 345 = **357** = sum of **A+C+C**, the common ends
of tRNA.

Sum of a triplet chain "inwards" 012-123-234-345
= **2 x 357**.

A-base 012+123 = 135, plus first two intervals = + 2 C-bases
111 = 357.

** ***B-chains as periodic numbers: *

**Fig 15-4:**

A note:

543**/**3 = 181 = Tyr, R + B

321**/**3 = 107 = Tyr R.

Two steps in the triplet series = -222 = 3 x 74, the normal B-chins unbound

**Two more numbers **from the elementary chain 5 - 0:

4/5 + 3/4 + 2/3 + 1/2 = 1/2 x **5,43**3333

[1/5 + 1/4 + 1/3]4 = 376,5. x 10-3; x 2 x 103 = **753**,037.

About the elementary series as exponents to 2 as a binary lnguage and Serine, see file

**17.16.point 6**.

**II. The x**^{4} series:

The x^{4} series as an underlying chain?

It would agree with the general thoughts behind this research that
chains as x^{4} and x^{3} (x = 5 - 0) could underlie
the ES-chain on deeper levels.

In the chain, figure 15-2 below, we have that 625 - 81 = 544, the
G+C-coded ams and 625 + 256, + 81 = 962, the U+A-coded ams +2. The
operation -**/**+ 81 in this series x^{4} is comparable
with the similar operation -**/**+ 208 in the ES-chain.

**Fig 15-5:** * An
x*^{4}-chain, some codon groups of ams:

Number 81 is both a charged molecule H2PO3 but also the R-chain
of His (the only ams that not derives from Glycolysis-Citrate cycle
but from the A-base).

It could be observed that -/+ 81 gives the individual
codon base groups in 1st order in the ES-chain:

½ x 544
-/+ 81 = G1 191, C1 353,

544 - 81 = U1 463

416 + 81 = A1 497. (An eventual influence
of phosphorus groups, P-group H2PO3~ = 81 or of His, R 81?)

Sum 4^{4} + 3^{4} = 337 is 1/3 of the total sum
of the ES-chain.

*

**To** **An x3-chain ?**