__1. Total sum R+B-chains of 24 ams unbound = 3276____:__

3276 is about 1**/**10 of 2^{15}. In nb-16 it's CCC, which
may be transcribed as

12.12.12 = 3072 (3 x 322 = 4 x 768) + 192 + 12:

*Fig 18-1**:* Total
sum of 24 ams R+B:

(2 π x 100:
the bound 24 ams as a closed circle!)

12.12.12: An association goes to carbon ^{12}C and the 3C-molecules
from halved fructose in glycolysis from which first group of ams
derives. Could we eventually read positions of the carbon atoms
as decided and guided by oxygen ^{16}O in some way?! Much
of the process in glycolysis seems to be about a stepwise displacement
of oxygen along the C-C-C-chain.

__2. Why 24 ams?__

One reason to suspect nb-transformations could be the 4 double-coded
ams, If 20 ams have to be 24, then 4 ams must be repeated (!).

20**-10** → 24**-8**

__3. H-atoms, 152 in R-chains: and the total of R 1504:__

Number of hydrogen atoms in R-chains was 152 = interval 4'- 1' in
the ES-series.

292 — 252 —208 —— 159 —
100 — 0

———**-|**<-44-><**|**——108——>**|**

This interval is divided 4'-3' = 44 and 3'-1' = 108: Transformed
from nb-16 to nb-6 they give total Z-numbers of R-chains and N-numbers
separately:

**Fig 18-2: ***H-atoms:*

Steps 44 → 152 = + **108**

Step 108 → 676 = + 568...This
sum is also = 676 = Z (or N) of atoms C, N. O, S.

Cf. 676 = 26^{2} and the 2x^{2}-chain,file 13.

__4. N-numbers in codon-groups of ams may lead to totals of ams:__

*Fig*. *18-3:* Neutron numbers to totals

__5. Number of C-atoms in R-chains as basis for divisions:__

In file 04, para. 3, the ams were ordered after number of C-atoms in their R-chains and their mass summed. This division did not concern codon distribution but seemed related
to the ES-series with certain assumptions.
Here C for carbon. (8 ams with 4 C in R-chains got the sum 584 2 x 292.)

Phe and Tyr are synthesized as 3C- plus 4C-molecules,
hence positioned between 4C- and 3C-.groups. Trp as 3C + 4C + 5C
- 1C. Trp gets its B-chain from Ser, shares codon with Cys and can
brake down to Ala, hence here regarded as "meeting the other
way around", added to the l C group.

*Fig. 18-4a:* Transformations along the ES-chain as a nxC-chain:

*Fig. 18-4b:* Cf. triplet sums, file 15, numbers 714 and 792:

**Fig. 18-4c:** nxC-atoms - three more details:

__6. B-chains:__

**6.1 Number 752, sum of first 3 numbers in the ES-chain:**

a) 752 from nb-**16** to nb-**10** gives the total **1772** of
24 B-chains unbound:

**292**-**16** →
658-**10**

**252**-**16** →
594-**10**

**208**-**16 ****→ ** 520-**10**...
sum **1772**, 24 B-chains unbound

Cf. that 752: nb-**10** gave **2848** in nb-**6**, i.e., R+B-chains
of 24 ams bound:

*Fig. ***18-5:**

**6.2 A single, unbound B-chain = 74:**

Two sets of the 4 RNA-bases, sum 1018, gave in nb-8 the
sum of 24 B-chains unbound = 1772. A single unbound B-chain à 74 gives the
sum of 2 bound B-chains.

*Fig 18-6: *From one unbound
B-chain to two bound ones:

6.3 Halvings of 2 x 5' 584 transformed to unbound and bound B-chains:

*Fig. 18-7:* From
number 5´ in the ES-chain to B-chains in groups of 6:

6.4 Total B-chains unbound times 2 from the 4 bases:

**Fig. 18-8:**

**6.5 Total of bound B-chains = 1344 from the bases: **

*Fig. 18-9:*

6.6 Hypoxanthine 136 in repeated steps gives B-chains bound or unbound:

__ Hypoxanthine__ 136 A (1**/**4 x 544) may give both B-chain
numbers 1344 and 1772 bound and unbound through 4 steps of transformations:

**Fig. 18-10:**

*Note that without rewritings 530 ~ 528 and 1020 ~ 1018 we get
1776 (24 x 74 A).

**7. Displacements between 1st and 2nd base order: Numbers 220 - 26:**

**7.1 Relations between displacements 220 and** 26:

**Fig. 18-11:**

*Fig 18-12:*

The relations between displacement 220 in the G+C-group and 26 in the U+A-group could be explained through only a minus 1 in N- and Z parts and the results in nb-8 through transformations.

Regard number 144 in figure 18-11 above divided in 64 and 80:

**Fig. 18-13:** How the displacement 220 and 26 could be explained through -1:

*Fig. 18-14:*

**7.2 The number 220 in displacements in group G+C:**

**Fig. 18-15:**** **

__8. The 4 double-coded ams, sum = 246__

The sum of R-chains of the 4 ams with two different codons are "also" 246,

i.e., the sum of displacements 220 and 26 above.

All 4 may become 37 in different nb-systems.

**Fig. 18-16:**

*

To **P-groups**